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v^2+6v-112=0
a = 1; b = 6; c = -112;
Δ = b2-4ac
Δ = 62-4·1·(-112)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-22}{2*1}=\frac{-28}{2} =-14 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+22}{2*1}=\frac{16}{2} =8 $
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